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wilberforce-pendulum
Models
These models and simulations have been tagged “wilberforce-pendulum”.
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
LAJPE energy Wilberforce
Michele D'Anna
15
2 days ago
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
GIREP-2025 Wilberforce normal mode col trucco
Michele D'Anna
2 days ago
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
GIREP-2025 Wilberforce
Michele D'Anna
3
2 days ago
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
GIREP-2025 Wilberforce beats
Michele D'Anna
2 days ago
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
prova figura GIREP-2025 Wilberforce normal mode
Michele D'Anna
yesterday
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
GIREP-2025 Wilberforce energy
Michele D'Anna
4
2 days ago
k
=31.8 N/m,
m
=0.493 kg
I
=0.000102 kg m^2
D
=0.0066 N m /rad^2
ε = 0.0244 N/rad
b=0.0042 N s/m,
β =0.00000087 N m s /rad^2
z0=0.0245 m
α0=0rad
Figure ENERGY GIREP Wilberforce
Michele D'Anna
2 days ago
